1221C - Perfect Team - CodeForces Solution

binary search math *1200

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Python Code: 




import sys
input = sys.stdin.readline




for _ in range(int(input())):
    c, m, x = map(int,input().split(' '))
    t=0
    a=min(c,m)
    if x >= a:
        print(a)
    else:
        t=t+x
        c=c-x
        m=m-x
        x=0
        t=t+min(min(m,c),(m+c)//3)
        print(t)

C++ Code: 

#include <stdio.h>

int main()
{
    int tc;
    scanf("%d", &tc);
    while(tc--){
        long long a, b, c, mini, temp;
        scanf("%lld %lld %lld", &a, &b, &c);
        if((a==0)||(b==0)){
            printf("0\n");
        }
        else{
            long long sum=a+b+c;
            if(a<=b){mini=a;}
            else    {mini=b;}
            temp = sum-mini*2;
            if(temp>=mini){
                printf("%lld\n", mini);
            }
            else{
                printf("%lld\n", sum/3);
            }
        }
    }

    return 0;
}


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